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Using a Link and File URL directly

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Author	Message
Matthew Knell	Tuesday 01 July 2003 10:05:59 am In ez 3.1.1 - I can't seem to find an easy way to do this - instead of going through the node page, I want to access a file URL directly, or a link URL directly - what's the code I would use to get the URL object? I added "attribute" to my page to see what it said, and there was nothing remotely close to it - I didn't see it in the docs. Thanks as always for your assistance.
Paul Forsyth	Tuesday 01 July 2003 10:30:18 am Are you talking about a ezurl datatype or a url that has been transformed by the ezurl function? If it is the latter look at the html source of your page to deduce the correct link. paul
Matthew Knell	Wednesday 02 July 2003 8:03:01 am First, thanks for your resposnse - your help is greatly appreciated. Let me lay out the example so it makes a little more sense- It's sort of two questions in one, and again, I appreciate your help. I've created an object called Press Releases. On each one of the pages, I've modified the full template to call in the children of Press Releases. I have two different types of children on the press release page - URL (for links related to the press release) and File (for files that accompany a release). So lets say I use Yahoo Finance as a link, and the link URL I entered as a URL is http://finance.yahoo.com/, and a File called Release.ppt as a file. When I pull in the children using a fetch object called files (for files) and a different fetch object called links (for the URLs), I output them using the standard node_gui_view: {section name=File loop=$files} {node_view_gui view=line content_node=$File:item}<br /> {/section} This returns me the URL to the node page related to the link (lets say /user/content/view/118), and the node page related to the file (lets say /user/content/view/119) - not http://finance.yahoo.com/ or the URL direct to Release.ppt (something like /user/content/download/141/578/file/Release.ppt) - . What I want to access is the direct URL itself - (to the http://finance.yahoo.com page and the /user/content/download/141/578/file/Release.ppt). I want to skip the node page and go directly to the file. Thanks again. >> I sorta figured it out - I'm using {attribute_view_gui} instead of just outputting the value, which is great - new question is tho - how do I remove the <p> around the attribute_view_gui output for descriptions - Thanks again.

Author

Message

Tuesday 01 July 2003 10:05:59 am

In ez 3.1.1 - I can't seem to find an easy way to do this - instead of going through the node page, I want to access a file URL directly, or a link URL directly - what's the code I would use to get the URL object? I added "attribute" to my page to see what it said, and there was nothing remotely close to it - I didn't see it in the docs.

Thanks as always for your assistance.

Paul Forsyth

Tuesday 01 July 2003 10:30:18 am

Are you talking about a ezurl datatype or a url that has been transformed by the ezurl function?

If it is the latter look at the html source of your page to deduce the correct link.

paul

Matthew Knell

Wednesday 02 July 2003 8:03:01 am

First, thanks for your resposnse - your help is greatly appreciated.

Let me lay out the example so it makes a little more sense- It's sort of two questions in one, and again, I appreciate your help.

I've created an object called Press Releases. On each one of the pages, I've modified the full template to call in the children of Press Releases. I have two different types of children on the press release page - URL (for links related to the press release) and File (for files that accompany a release). So lets say I use Yahoo Finance as a link, and the link URL I entered as a URL is http://finance.yahoo.com/, and a File called Release.ppt as a file.

When I pull in the children using a fetch object called files (for files) and a different fetch object called links (for the URLs), I output them using the standard node_gui_view:

{section name=File loop=$files}
{node_view_gui view=line content_node=$File:item}<br />
{/section}

This returns me the URL to the node page related to the link (lets say /user/content/view/118), and the node page related to the file (lets say /user/content/view/119) - not http://finance.yahoo.com/ or the URL direct to Release.ppt (something like /user/content/download/141/578/file/Release.ppt) - . What I want to access is the direct URL itself - (to the http://finance.yahoo.com page and the /user/content/download/141/578/file/Release.ppt). I want to skip the node page and go directly to the file.

Thanks again.

>> I sorta figured it out - I'm using {attribute_view_gui} instead of just outputting the value, which is great - new question is tho - how do I remove the <p> around the attribute_view_gui output for descriptions -

Thanks again.