Add a login/logout link

Thursday 29 July 2004 8:39:26 am

In my pagelayout.tpl , I'd like to add a login/logout link (I need it in all my pages).
I've tried this but I get some errors:

<!-- Main menu table -->
            <table cellspacing="0" cellpadding="0" class="menu">
                <tr>
                    <td><a href={"/"|ezurl}>Home</a></td>
		    <td><a href={"/news"|ezurl}>News</a></td>
		    <td><a href={"/membres"|ezurl}>Memberss</a></td>
		    <td><a href={"/guestbook"|ezurl}>Guestbook</a></td>
		    <td><a href={"/links"|ezurl}>Links</a></td>
                    <td><p class="menuitem">
                      {section show=eq($current_user.contentobject_id,$anonymous_user_id)}
<a href={"/user/login/"|ezurl}> Login </a>
                    {section-else}
<a href={"/user/logout/"|ezurl}> Logout </a> 
                    {/section}
                    </p></td>
                </tr>
            <!-- End of main menu table -->

Can someone tell me how to realize this. May be there is another way ?
Thanks.

Thursday 29 July 2004 4:14:27 pm

Try this. I've used if before

{let thisuser=fetch('user','current_user')}
  {section show=$thisuser.is_logged_in}
<p>Welcome. You are logged in as {$thisuser.contentobject.name}</p>
<p><a href={"/user/logout"|ezurl}>Logout</a></p>
  {section-else}
  
<p><a href={"/user/login/"|ezurl}> Login</a></p>                                                                                
  
  {/section}
{/let}
</div>

Cheers
Bruce http://www.designit.com.au/

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