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Monday 02 May 2005 3:56:01 am
I have use the same templates which is given in tutorial to show all child of main folder, which is as follws:
{* Grab all the child nodes. *}
{let children=fetch( content, list, hash( parent_node_id, $node.node_id,
sort_by, $node.sort_array ))}
<table class="accueil_list" cellpadding="0" cellspacing="0" border="0">
{* Loop through all nodes that we just fetched. *}
{section name=Child loop=$children}
{* Output the name as a link to the node containing the member. *}
<tr>
<td>
{node_view_gui view=line content_node=$Child:item}
</td>
</tr>
{* End of loop. *}
{/section}
</table>
{/let} But I my site, I want to change this templates like that it does not show all the child name but just one class description, means I need just the description of the subclass which I had created under the main folder, and not display the name of all child which is created under the same folder. I try to do that can't successed, any body tell me what exactly I had to do change. I had already created line view templeate for that sub class and i can obtained that class view successfully when I click on that main folder, but due to above templates, the rest child name is also apper on the front page, which I want to remove. Thanks
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