Is it possible to undef a varible whis is not defined

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Author	Message
Jose Mourinho	Sunday 09 September 2007 1:22:43 pm Hello all Is it possible to undef a variable which is not defined? And I have one more question... The function is_set($var) returns true if $var is defined or have value different from '' 10x all
André R.	Sunday 09 September 2007 1:31:13 pm Why would you want to undefine a variable that is not defined?? Are you talking about undefine a variable if it is defined? like this: {if is_set( $my_var )} {undef $my_var} {/if} is_set: http://ez.no/doc/ez_publish/technical_manual/3_9/reference/template_operators/variable_and_type_handling/is_set eZ Online Editor 5: http://projects.ez.no/ezoe \|\| eZJSCore (Ajax): http://projects.ez.no/ezjscore \|\| eZ Publish EE http://ez.no/eZPublish/eZ-Publish-Enterprise-Subscription @: http://twitter.com/andrerom
Jose Mourinho	Sunday 09 September 2007 2:19:49 pm Yes I want to do this but in the example at http://ez.no/doc/ez_publish/techn...rs/variable_and_type_handling/is_set {def $whatever='We need more rocket fuel!'} {if is_set( $whatever )} It is set. {else} It is not set. {/if} but $whatever has a value ... I want to know if the variable is defined. I don't want to know if variable has some value ...
Felix Laate	Sunday 09 September 2007 2:54:37 pm But this is the excact function of the is_set operator, after all the doc reads: Returns TRUE if the value of the provided variable is set. Felix Publlic Relations Manager Greater Stavanger www.greaterstavanger.com
Peter Putzer	Sunday 09 September 2007 3:53:34 pm Unfortunately, is_set() returns false if the value of the inspected variable is false. For most common applications (checking whether a variable is set before either using its value or a default), first_set() is the proper workaround. Accessible website starting from eZ publish 3.0 (currently: 4.1.0): http://pluspunkt.at