|
Author
|
Message
|
|
Björn [email protected]
|
Tuesday 24 June 2003 3:51:54 pm
I have been looking in serveral arrays for the the current site access.
I searched the following arrays. Where is it? If it really doesn't exist in one of those var we should add it to one of the arrays. $DesignKeys preferred. THX Björn
{$site|attribute(show)}
{$site.uri|attribute(show)}
{$DesignKeys:used|attribute(show)}
{$DesignKeys|attribute(show)}
{$module_result|attribute(show)}
{$module_result.content_info|attribute(show)}
Looking for a new job? http://www.xrow.com/xrow-GmbH/Jobs
Looking for hosting? http://hostingezpublish.com
-----------------------------------------------------------------------------
GMT +01:00 Hannover, Germany
Web: http://www.xrow.com/
|
|
Selmah Maxim
|
Wednesday 25 June 2003 1:17:22 am
try this : {ezini('SiteSettings','SiteURL')}
|
|
Björn [email protected]
|
Wednesday 25 June 2003 6:32:12 am
{ezini('SiteSettings','SiteURL')}
gives
www:92
Thats not it.... That's the simple siteurl. my access types are called "english" and "german"
Looking for a new job? http://www.xrow.com/xrow-GmbH/Jobs
Looking for hosting? http://hostingezpublish.com
-----------------------------------------------------------------------------
GMT +01:00 Hannover, Germany
Web: http://www.xrow.com/
|
|
Bård Farstad
|
Thursday 10 July 2003 5:30:30 am
And the answer is: {$access_type.name} A bit late though ;) --bård
Documentation: http://ez.no/doc
|
|
Jan Komárek
|
Monday 09 August 2010 9:58:57 am
Its functional only in pagelyout for me. Is any way how to do this in non layout template?
|
|
Kévin S.
|
Tuesday 10 August 2010 2:41:37 am
You can use template parameters :
{include uri='design:template_name.tpl' accessType=$access_type.name}Then in your 'template_name.tpl' you just have to call the given parameter as a variable :
{$accessType|attribute(show, 1)}It works for view templates as well as system templates.
|
|
Jan Komárek
|
Tuesday 07 September 2010 10:14:00 am
"
It works for view templates as well as system templates.
"
I am not sure what you mean by system template. But I still have no idea how can I get $access_type in for example content/view/full/article.tpl. Thank you very much.
|
|
Abdelkader RHOUATI
|
Tuesday 07 September 2010 5:32:44 pm
Hi, I had the same problem today, for solution i used a template operators "current_siteaccess" available in the extension swark (http://ez.no/developer/contribs/template_plugins/swark). In addition to this operator, the extension provides severals PHP's functions that are not in the list of defaults operators of ezpublish. I use it in almost all projects. And most important "current_siteaccess" works in every template ;). TKS.
Abdelkader RHOUATI
Blog (french) : http://arhouati.com
----
Extension arh_jdebug : EzDebug using jquery
|
|
Jan Komárek
|
Friday 10 September 2010 8:41:41 am
Thank you, thats it!
|
