contentobject status 5

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Claudia Kosny	Thursday 09 November 2006 12:37:00 am Hi there I have created a new datatype which stores some data in an external table. In the function objectAttributeContent(...) I either want to fetch the data for the current version or, if the current version is a draft, the data of the published version. The prolem I have is determining whether the the current version is a draft. My current code is like this: $currentVersion =& $contentObjectAttribute->attribute('object_version'); $currentVersionNr = $currentVersion->attribute('version'); $currentVersionStatus = $currentVersion->attribute('status'); The version number is correct, but the status is set to 5. According to the documentation the status for a draft is supposed to be 0, a status of 5 is not mentioned at all. Any idea what is going on? Claudia
Paul Forsyth	Thursday 09 November 2006 1:43:32 am What type of object does your datatype return as content? Looking at the object version class i see this: define( "EZ_VERSION_STATUS_DRAFT", 0 ); define( "EZ_VERSION_STATUS_PUBLISHED", 1 ); define( "EZ_VERSION_STATUS_PENDING", 2 ); define( "EZ_VERSION_STATUS_ARCHIVED", 3 ); define( "EZ_VERSION_STATUS_REJECTED", 4 ); //define( "EZ_VERSION_STATUS_SHOWN", 5 ); which shows that status 5 is not used. perhaps your datatype returns something else? paul
Claudia Kosny	Thursday 09 November 2006 2:37:48 am Hi Paul here is the result of print_r($currentVersion): ezcontentobjectversion Object ( [PersistentDataDirty] => [CurrentLanguage] => [ContentObjectAttributeArray] => [DataMap] => [TempNode] => [VersionName] => [VersionNameCache] => Array ( ) [ID] => 738 [ContentObjectID] => 201 [CreatorID] => 14 [Version] => 5 [Status] => 5 [Created] => 1163067858 [Modified] => 1163067858 [WorkflowEventPos] => 0 [UserID] => 0 [LanguageMask] => 3 [InitialLanguageID] => 2 ) As you can see I get a contentobjectversion as it should be.The object and the version itself is also correct, I can access the current content of all attributes correctly. I get similar data for the current version if I fetch all versions of the object using contentobject->versions(false) and then check the data for the version that is currently edited. Maybe a draft is only a draft with status 0 if it was stored as draft and the status 5 is simply for a toally new version? I have not checked any further as I spent already a considerable amount of time finding out why my code did not work as expected.At the moment my code works fine if I check for status equals 5 or 0 so I will leave it at that for now (unless you can point me to a better solution) Regards Claudia
Paul Forsyth	Thursday 09 November 2006 2:50:39 am Just had a quick look at the latest eZ version and indeed it does have a new value: define( "EZ_VERSION_STATUS_INTERNAL_DRAFT", 5 ); It allows the system to clean up objects which never became published. So, your object is a system-created draft. Testing for both 0 and 5 will work. Read this for more info: http://pubsvn.ez.no/nextgen/trunk/doc/features/3.8/temporary_drafts.txt Paul
Claudia Kosny	Thursday 09 November 2006 3:03:58 am Hi Paul Thanks a lot - now I don't need to worry whether my code will work or not. I will add the information to the online documentation. Claudia