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Mieczyslaw Morzonek
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Tuesday 06 July 2004 6:08:01 am
I`ve the url somthing like this ez/index.php/cms/trainees?mode=false&id=181 I want to sort by attribute 181, so i i`ve write something like this
fetch( 'content', 'list', hash( 'parent_node_id' ,
$node.node_id,
'sort_by' ,
array('attribute' , concat(ezhttp( 'mode', 'get' ),"()")
, ezhttp( 'id', 'get' )),
'class_filter_type' , 'include',
'class_filter_array', array( 'trainee' ) ) )}
I can not sort by ASC or DESC. The problem is in (ezhttp( 'mode', 'get' ),"()"). I don`t know how to construct true() or false form my URL. This source code (ezhttp( 'mode', 'get' ),"()") is not VISIBLE for the FETCH function. Thanks for any help
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Paul Forsyth
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Wednesday 07 July 2004 3:26:37 am
Sometimes its good to separate out different function calls, eg:
{let getMode=ezhttp('mode','get')
getID=ezhttp('id', 'get')
result=fetch( 'content', 'list', hash( 'parent_node_id' , $node.node_id,
'sort_by' , array('attribute' , concat($getMode,"()", $getID)),
'class_filter_type' , 'include',
'class_filter_array', array( 'trainee' ) ) )}
paul
--
http://www.visionwt.com
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Mieczyslaw Morzonek
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Wednesday 07 July 2004 5:42:14 am
Paul thank you for your idea, but it doesn`t work. I ve change part of your code {concat($getMode,"()", $getID)} to {concat($getMode,"(), ", $getID)} now the last parametr "ID" in`t visible for fetch function. I ve sql error ...
Query error: Something is wrong in your syntax near 'AND
a0.version = ezcontentobj' in linie 18
WHERE
path_string like '/1/2/67/%' and depth <= 3 and
a0.contentobject_id = ezcontentobject.id AND
a0.contentclassattribute_id = AND // line 18
a0.version = ezcontentobject_name.content_version AND
a0.language_code = ezcontentobject_name.real_translation AND
Any other idea how to sort data in table via columns ASC or DESC clicking column name? Is it {if} operator in ez templates? {if $var == something} ... syntax {elseif $var == something} ... syntax {/if} i ve also traing like this but it`s still doesn`t work
getMode=concat(ezhttp('mode','get'),"()")
I don`t know why? How to submit this 2 variables "mode" and "id" to fetch function? I lost hope to solve this problem :( Is this a somekind of bug?
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Paul Forsyth
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Wednesday 07 July 2004 1:30:13 pm
THere is an 'if' operator. Use section:
{section show=eq($test, 1)}
Do something
{section show=eq($test, 2)}
Do something different
{/section}
{section-else}
Do something else
{/section}
Are you looking to create a true/false value for your sort_by array? Putting in text wont work - the value needs to a proper true/false value. Hope this helps paul
--
http://www.visionwt.com
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Paul Forsyth
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Thursday 08 July 2004 3:56:35 am
Excellent. Yip, i feel using sections for ifs are clumsy. The benefit is that section can be used for lots of other things. At the end of the day it is just another language syntax that we have to learn as programmers. I've learnt lots of languages in my time and quickly learnt not to worry about naming choices :) paul PS. Very weird error. Edits appear in two places..............:
--
http://www.visionwt.com
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