|
Author
|
Message
|
|
Lo' F.
|
Monday 27 September 2010 9:56:43 am
Hello again, Having a little trouble getting the current page node id from a content/view/line.tpl, where I need to compare the line embedded object node id to the current page node id. Any suggestion would be highly appreciated.. meanwhile I'll keep tryng..
loredanaebook.it
|
|
Lo' F.
|
Monday 27 September 2010 11:44:22 am
Let's say I created 4 frontpages under the root node. In the right column of these frontpage objects I embedded, on a line view, each of them as links to the others. The thing is I need to deactivate the link of the one is already the displayed page. In order to accomplish this, I need to compare each {$object.main_node.node_id} to the current one. This {$object.main_parent_node_id} returns, of course, the root under which I created those nodes, and so far it's the only outcome I have been able to get. I need to create the conditional statement and so utilize the current page node_id in the content/view/line.tpl which is the template through which those links come from. ... hope somebody can help..
loredanaebook.it
|
|
Håvard Bergersen
|
Monday 27 September 2010 12:48:31 pm
If you have one template for all the subpages, you could do something like this: To create right column in subpage template:
{def $pages=fetch( 'content', 'list', hash( 'parent_node_id', 'something' ) )}
{foreach $pages as $p}
{node_view_gui content_node=$p view=line current_node_id=$node.node_id}
{/foreach}The lineview template
{if eq( $current_node_id, $node.node_id )}
{$node.name|wash()}
{else}
<a href={$node.url|ezurl}>{$node.name|wash()}</a>
{/if}This should work, but there may be a cache issue.
|
|
Lo' F.
|
Monday 27 September 2010 1:36:16 pm
Thank Håvard for your reply. I actually embedded those frontpage objects of the frontpage class from the admin back-end. And making the adjustments from the contentview/line.tpl template..
{default node_name=$object.main_node.name node_url=$object.main_node.url_alias}
<h2>{if $node_url}<a href={$node_url|ezurl}>{/if}{$node_name|wash}{if $node_url}</a>{/if}</h2>
{/default} Here the $current_node_id doesn't work.. So far... among with all the attempts aimed to get the current page url (..unable to get the node_id from here I was trying to get the current page url)...: - {ezpagedata().path|ezurl} or {$module_result.path|ezurl} return a too short result ( "/index.php/ita" ) - {$child.url|ezurl()} too long ( "/index.php/ita/the-page-I-need/its-last-child/its-last-child's-last-child" )
loredanaebook.it
|
|
Håvard Bergersen
|
Monday 27 September 2010 1:44:14 pm
Ahhh... Okey.... Well,,could you use {$module_result.node_id} ? Or {$module_result.path_array} {if $module_result.path_array|contains( $node.node_id )} ? Or am I not understanding anything now hehe... :)
|
|
Lo' F.
|
Monday 27 September 2010 2:12:25 pm
.. you have almost sorted my problem out..! At least I am starting getting something that is probably far from what I should do but kind of.. working after all... See how it comes:
{if $child.url|ezurl|contains($object.main_node.url)}
{$node_name|wash}
{else}
<a href="{$node_url|ezurl}">{$node_name|wash}</a>
{/if} ..it could be a cover for the time being... but if I could get a proper current page node_id either its url should be better..
loredanaebook.it
|
|
Håvard Bergersen
|
Monday 27 September 2010 2:19:36 pm
{if $node.path_array|contains( $object.main_node.node_id ) }Maybe a little cleaner :) You can't reach the current node id outside the pagelayout.tpl...
|
|
Lo' F.
|
Monday 27 September 2010 2:28:33 pm
"
{if $node.path_array|contains( $object.main_node.node_id ) }Maybe a little cleaner :) You can't reach the current node id outside the pagelayout.tpl...
"
{$node.path_array|ezurl} returns "/index.php/ita"
loredanaebook.it
|
|
Håvard Bergersen
|
Monday 27 September 2010 2:31:17 pm
{$node.path_array} returns an array of node id's.. So you can't use the |ezurl operator on it :)
|
|
Lo' F.
|
Monday 27 September 2010 2:39:06 pm
"
{$node.path_array} returns an array of node id's.. So you can't use the |ezurl operator on it :)
"
..okey.. but yet it didn't return nothing when I tried it in the {if} condition...
loredanaebook.it
|
|
Håvard Bergersen
|
Monday 27 September 2010 2:43:28 pm
Hm.... Just tested it and it works here.. Tried dumping all the variables to inspect it? {$node.path_array|attribute(show)}
{$object.main_node|attribute(show)}
Well,, good luck & good night :)
|
|
Lo' F.
|
Monday 27 September 2010 3:22:45 pm
..nope... Only {$object.main.node|attribute{show}} works from here (..content/view/line.tpl) while {$node.path_array|attribute(show)} returns an empty Attribute Type Value. ... We'll see tomorrow. Good night!
loredanaebook.it
|
|
Nathan Kelly
|
Monday 27 September 2010 11:09:56 pm
If {$object.main_node|attribute(show)} is working you should be able to get the path_array with
{$object.main_node.path_array|attribute(show)}(keep in mind however if your node is placed in more than one location this will only find the main_node path_arry which will be different to any of the co-located nodes.)
Pardon me while I burst into flames...
|
|
Bayron Guevara
|
Monday 27 September 2010 11:59:23 pm
I think you are trying to call a global variable inside a content view, from here you need to use the # character to indicate access to the global scope. So maybe the following code solve your problem:
{if eq($#module_result.node_id, $object.main_node_id)}
{$node_name|wash}
{else}
<a href="{$node_url|ezurl}">{$node_name|wash}</a>
{/if}
Web Developer & Modern Philosopher
Visit http://www.laprensa.hn, http://www.diez.hn, http://www.estilo.hn
|
|
Lo' F.
|
Tuesday 28 September 2010 4:02:49 am
"
I think you are trying to call a global variable inside a content view, from here you need to use the # character to indicate access to the global scope. So maybe the following code solve your problem:
{if eq($#module_result.node_id, $object.main_node_id)}
{$node_name|wash}
{else}
<a href="{$node_url|ezurl}">{$node_name|wash}</a>
{/if}
"
Thank you guys, but this doesn't work too.. I thought that could have worked because in theory that's what I am trying to do... The only way I can get the current object page from the content view seems to be through its $child,
{if $child.path_array|contains($object.main_node.node_id)}ok{/if}even though this is not the answer 'cause if there are not children in there it has no sense at all..
loredanaebook.it
|
|
Kévin S.
|
Thursday 30 September 2010 9:33:25 am
Hi Lo'F ! I had a similar problem recently. I solved it using ezhttp operator and a HTML GET parameter, which was the id of the node to display. You can find more information in this topic. Hope it'll help ! ___ Kévin
|
|
Lo' F.
|
Saturday 09 October 2010 7:47:28 am
"
I had a similar problem recently. I solved it using ezhttp operator and a HTML GET parameter, which was the id of the node to display.
"
Hi Kévin! Thanks to your hint I finally got the perfect solution! Your ezhttp took me here http://doc.ez.no/.../Template-operators/Data-and-information-extraction where I came across this module_params Made it run this way ..
module_params()|attribute(show) I got this outcome...
"
| Attribute
| Type
| Value
|
| module_name
|
string
|
'content'
|
| function_name
|
string
|
'view'
|
| parameters
|
array
|
Array(2)
|
| >ViewMode
|
string
|
'full'
|
| >NodeID
|
string
|
276
|
"
and...
{module_params()[parameters][NodeID]}gave me the node id I was looking for, so I eventually made it work!
{if module_params()[parameters][NodeID]|eq($object.main_node.node_id)}...Thank you again!
loredanaebook.it
|
|
Kévin S.
|
Tuesday 12 October 2010 5:20:23 am
Oh, nice ! Didn't find this one, very useful (I knew ezpublish could not let us without the current node ID !) Thank you for telling how you solved this problem ! ___ Kévin
|